[PHP]字串比對-身份證比對,mail比對

service@hotmail.com.tw","linda@123454","1234@hinet.com");
//定義樣式$ptn1="[a-z]{1}[1-2]{1}[0-9]{8}";
for($a=0;$a 格式正確

"; }else{ echo $id[$a]." => 格式不正確

"; }}
//找尋開頭可以是任何英文或數值,接著有一個@其後還有一個點$ptn2="^[[:alnum:]]+@[[:alnum:]]+\.";
for($a=0;$a 格式正確

"; }else{ echo $mail[$a]." => 格式不正確

"; }}?>